This problem is from concept 10, and in this problem we are basically find it's zeroes. But in order to find them we must find the p's and q's and the possible positive and negative real zeroes. Then we use synthetic and probably the quadratic formula. Well to really sum up, if you know how to do concept 6 then your good.
The part I suggest you should pay attention to is when your finding the two zero heroes. 1 and -1 will not always work so your going to use the rest of the p's and q's and it would get tricky. I suggest you use the fractions first when whole numbers, it would be a bit easier.
Saturday, September 28, 2013
Monday, September 16, 2013
SP#2: Unit E Concept 7 - Graphing a polynomial and identifying all key parts
Factoring: First factor the equation fully. Then we can take out x^2 from the original equation. We an distribute x^2+3x+2 even more to (x+2) (x+1).
End Behavior: By looking at the leading coefficient and the exponent,we know that it is an even positive.
X-intercept: With the variables, we know that there should be 4 zero multiplicities because the leading exponent is 4. Since 0 has the multiplicity of 2 then the line bounces off of its point. -2 and -1 have the multiplicity of 1 then the line goes threw them.
Y-intercepts: We replace the x's with 0 and multiply it with it's coefficient. Since it equals 0, then the y-intercept it 0.
This problem is about finding multiplicities and graphing it's points. While we do that we are also identifying all of it's parts as we go along. Then we graph the polynomial according to it's points.
To understand this concept, the viewer must first look at the leading coefficient and the exponent to see how many zero multiplicities there are and how the graph is suppose to look like. When they are done factoring the polynomial, they must see if the number of zero multiplicities are the same as the leading exponent.
End Behavior: By looking at the leading coefficient and the exponent,we know that it is an even positive.
X-intercept: With the variables, we know that there should be 4 zero multiplicities because the leading exponent is 4. Since 0 has the multiplicity of 2 then the line bounces off of its point. -2 and -1 have the multiplicity of 1 then the line goes threw them.
Y-intercepts: We replace the x's with 0 and multiply it with it's coefficient. Since it equals 0, then the y-intercept it 0.
This problem is about finding multiplicities and graphing it's points. While we do that we are also identifying all of it's parts as we go along. Then we graph the polynomial according to it's points.
To understand this concept, the viewer must first look at the leading coefficient and the exponent to see how many zero multiplicities there are and how the graph is suppose to look like. When they are done factoring the polynomial, they must see if the number of zero multiplicities are the same as the leading exponent.
Tuesday, September 10, 2013
WPP #4: Unit E Concept 3 - Maximizing Area
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Monday, September 9, 2013
WPP#3: Unit E Concept 2 - Path of Football
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Sunday, September 8, 2013
SP#1: Unit E Concept 1 - Graphing a quadratic and identifying all key parts
SP# 1: Unit E Concept 1: Identifying x and y intercept, vertex, axis of quad. and graphing them.
- Subtract 9 to both sides
- factor the left side and find the missing number which is 4
- then divide 3 to both sides
- square root both sides
- then subtract 2 to both sides
In this problem we identify the x-intercept, y-intercept, vertex, axis of quadratics, and we graph them. We first need to find the parent function before we do anything else like graphing.
The part that you should pay more attention to is when your solving for the x-intercept. Mine came out as whole numbers and that's easy because it doesn't need any more points. If is was a negative when it's imaginary, if it's not and it has a square root then it came be solved.
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